12y^4-3y^2+6y/3y^2

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Solution for 12y^4-3y^2+6y/3y^2 equation: 


y in (-oo:+oo)

12*y^4+((6*y)/3)*y^2-(3*y^2) = 0

12*y^4+((6*y)/3)*y^2-3*y^2 = 0

12*y^4+2*y^3-3*y^2 = 0

y^2*(12*y^2+2*y-3) = 0

12*y^2+2*y-3 = 0

DELTA = 2^2-(-3*4*12)

DELTA = 148

DELTA > 0

y = (148^(1/2)-2)/(2*12) or y = (-148^(1/2)-2)/(2*12)

y = (2*37^(1/2)-2)/24 or y = (-2*37^(1/2)-2)/24

y^2 = 0

1*y^2 = 0 // : 1

y^2 = 0

y = 0

y in { (-2*37^(1/2)-2)/24, (2*37^(1/2)-2)/24, 0 }

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